An ice skater with I = 6 kg m^2 spins at 3 rad/s, then pulls in her arms so I = 2 kg m^2. Her new angular velocity is:
- 9 rad/s
- 4.5 rad/s
- 18 rad/s
- 1 rad/s
Answer
A) 9 rad/s
I1omega1 = I2omega2 Rightarrow omega2 = 6 32 = 9 rad/s. SLO P-11-B-20 · Application
Physics MCQ · More Circular and Rotational Motion MCQs · Practise