Find the square root of x^29 - 23 + 1x^2.

  1. pm ( x3 - 1 )
  2. pm ( x3 + 1x )
  3. pm ( x3 - 1x )
  4. pm ( x9 - 1x )
Answer

C) pm ( x3 - 1x )

Expanding ( x3 - 1x )^2 gives x^29 - 23 + 1x^2, so its square root is pm ( x3 - 1x ). SLO M-09-A-20 · Understanding

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