The normal form of the line whose perpendicular from the origin has length 4 and makes an angle of 60^circ with the x-axis is:

  1. xcos 60^circ + ysin 60^circ = 4
  2. xcos 60^circ - ysin 60^circ = 4
  3. xcos 60^circ + ysin 60^circ = 16
  4. xsin 60^circ + ycos 60^circ = 4
Answer

A) xcos 60^circ + ysin 60^circ = 4

Normal form: xcosalpha + ysinalpha = p. Here this is x ( 12 ) + y ( 32 ) = 4. SLO M-09-B-08 · Understanding

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