A gas at constant pressure 3 10^5 Pa changes volume from 0.5 m^3 to 0.8 m^3. The work done by the gas is:
- 9000 J
- 90,000 J
- -90,000 J
- 9 10^5 J
Answer
B) 90,000 J
W = pDelta V = 3 10^5 (0.8 - 0.5) = 90,000 J. SLO P-11-C-06 · Application
Physics MCQ · More Kinetic Theory and First Law of Thermodynamics MCQs · Practise