A bucket of water is swung in a vertical circle of radius 2.5 m. The minimum speed at the top so the water stays in is (g = 9.8 m/s^2):
- 9.9 m/s
- 2.47 m/s
- 7 m/s
- 4.95 m/s
Answer
D) 4.95 m/s
At the minimum speed, weight alone provides the centripetal force: mg = mv^2r Rightarrow v = gr = 4.95 m/s. SLO P-11-B-15 · Application
Physics MCQ · More Circular and Rotational Motion MCQs · Practise