A gas exchanges no heat with its surroundings and does 150 J of work. The change in its internal energy is: (Use Q = Delta U + W, where Q = heat supplied to the gas and W = work done by the gas.)
- -150 J
- -300 J
- -1500 J
- -75 J
Answer
A) -150 J
Delta U = Q - W = 0 - (150) = -150 J. SLO P-11-C-08 · Application
Physics MCQ · More Kinetic Theory and First Law of Thermodynamics MCQs · Practise