A spring of constant 200 N/m stores 9 J of elastic energy. Its extension is:
- 0.3 m
- 0.09 m
- 0.15 m
- 0.6 m
Answer
A) 0.3 m
x = 2Ek = 2(9)200 = 0.3 m. SLO P-11-B-28 · Application
Physics MCQ · More Deformation of Solids MCQs · Practise
A) 0.3 m
x = 2Ek = 2(9)200 = 0.3 m. SLO P-11-B-28 · Application
Physics MCQ · More Deformation of Solids MCQs · Practise