A source of frequency 800 Hz moves at 40 m/s away from a stationary observer. The speed of sound is 340 m/s. The observed frequency is:
- 644 Hz
- 716 Hz
- 907 Hz
- 800 Hz
Answer
B) 716 Hz
fo = fs vv + vs = 800 340340 + 40 = 716 Hz. SLO P-11-D-03 · Application
Physics MCQ · More Wave Intensity and the Doppler Effect MCQs · Practise