The average translational kinetic energy of a gas molecule is:
- 32kT
- 12kT
- 3kT
- kT^2
Answer
A) 32kT
k = Boltzmann constant. SLO P-11-C-02 · Understanding
Physics MCQ · More Kinetic Theory and First Law of Thermodynamics MCQs · Practise
A) 32kT
k = Boltzmann constant. SLO P-11-C-02 · Understanding
Physics MCQ · More Kinetic Theory and First Law of Thermodynamics MCQs · Practise