A force of 20 N is applied tangentially at the rim (radius 0.5 m) of a wheel with I = 2 kg m^2. Its angular acceleration is:
- 2.5 rad/s^2
- 10 rad/s^2
- 5 rad/s^2
- 20 rad/s^2
Answer
C) 5 rad/s^2
tau = Fr = 10 N m; alpha = tau/I = 5 rad/s^2. SLO P-11-B-19 · Application
Physics MCQ · More Circular and Rotational Motion MCQs · Practise