Verify the distributive law of union over intersection: with A = 1, 2, 4, 6, 10, B = 1, 7, 8, 10, C = 1, 2, 4, 7, both A cup (B cap C) and (A cup B) cap (A cup C) equal:

  1. 1
  2. 1, 2, 4, 7
  3. 1, 2, 4, 6, 7, 10
  4. 1, 2, 4, 6, 7, 8, 10
Answer

C) 1, 2, 4, 6, 7, 10

Working out each side separately gives the same set 1, 2, 4, 6, 7, 10, which verifies A cup (B cap C) = (A cup B) cap (A cup C). SLO M-09-A-13 · Application

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