A car starts with velocity 0 m/s and accelerates at 4 m/s^2 for 3 s. The distance covered is:
- 9 m
- 18 m
- 19 m
- 36 m
Answer
B) 18 m
s = ut + 12at^2 = 0(3) + 12(4)(3)^2 = 18 m. SLO P-11-B-04 · Application
Physics MCQ · More Kinematics and Projectile Motion MCQs · Practise