A ball is projected at 50 m/s at 30^circ above the horizontal (g = 9.8 m/s^2). Its time of flight is:
- 8.84 s
- 2.55 s
- 10.2 s
- 5.1 s
Answer
D) 5.1 s
T = 2usinthetag = 2(50)(0.5)9.8 = 5.1 s. SLO P-11-B-05 · Application
Physics MCQ · More Kinematics and Projectile Motion MCQs · Practise