A hiker walks 24 km north and then 7 km east. Her distance and bearing from the start are:

  1. 25 km on a bearing of about 196.3^circ
  2. 25 km on a bearing of about 016.3^circ
  3. 31 km on a bearing of about 016.3^circ
  4. 25 km on a bearing of about 073.7^circ
Answer

B) 25 km on a bearing of about 016.3^circ

Distance = 24^2 + 7^2 = 25 km. Bearing = tan^-1 724 approx 16.3^circ (measured from north). SLO M-09-B-27 · Application

Mathematics MCQ · More Bearing MCQs · Practise