The internal energy of a gas increases by 150 J while it does 100 J of work. The heat supplied to it is: (Use Q = Delta U + W, where Q = heat supplied to the gas and W = work done by the gas.)
- 2500 J
- 500 J
- 250 J
- 125 J
Answer
C) 250 J
Q = Delta U + W = 150 + 100 = 250 J. SLO P-11-C-08 · Application
Physics MCQ · More Kinetic Theory and First Law of Thermodynamics MCQs · Practise