A hiker walks 5 km north and then 12 km east. Her distance and bearing from the start are:

  1. 13 km on a bearing of about 067.4^circ
  2. 17 km on a bearing of about 067.4^circ
  3. 13 km on a bearing of about 022.6^circ
  4. 13 km on a bearing of about 247.4^circ
Answer

A) 13 km on a bearing of about 067.4^circ

Distance = 5^2 + 12^2 = 13 km. Bearing = tan^-1 125 approx 67.4^circ (measured from north). SLO M-09-B-27 · Application

Mathematics MCQ · More Bearing MCQs · Practise