A current of 10 A flows through a 0.5 Ω resistor. The power dissipated is:
- 100 W
- 5 W
- 25 W
- 50 W
Answer
D) 50 W
P = I^2R = (10)^2(0.5) = 50 W. SLO P-09-E-12 · Application
Physics MCQ · More Current Electricity MCQs · Practise
D) 50 W
P = I^2R = (10)^2(0.5) = 50 W. SLO P-09-E-12 · Application
Physics MCQ · More Current Electricity MCQs · Practise