A gas at constant pressure 1 10^5 Pa changes volume from 0.001 m^3 to 0.003 m^3. The work done by the gas is:

  1. 20 J
  2. 2000 J
  3. -200 J
  4. 200 J
Answer

D) 200 J

W = pDelta V = 1 10^5 (0.003 - 0.001) = 200 J. SLO P-11-C-06 · Application

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