Each small square on a force–displacement graph represents 2 N × 0.5 m. 40 squares lie under the curve. The work done is:

  1. 20 J
  2. 80 J
  3. 100 J
  4. 40 J
Answer

D) 40 J

Each square = 1 J, so 40 J. SLO P-11-B-30 · Application

Physics MCQ · More Work and Energy MCQs · Practise