A wheel with moment of inertia 0.5 kg m^2 spins at 20 rad/s. Its angular momentum is:
- 10 kg m^2/s
- 200 kg m^2/s
- 20 kg m^2/s
- 5 kg m^2/s
Answer
A) 10 kg m^2/s
L = Iomega = 10 kg m^2/s. SLO P-11-B-18 · Application
Physics MCQ · More Circular and Rotational Motion MCQs · Practise