Water (rho = 1000 kg/m^3) flows horizontally. At one point P = 2 10^5 Pa and v = 2 m/s; at another v = 6 m/s. The pressure there is:
- 92,000 Pa
- 1.84 10^6 Pa
- 3.68 10^5 Pa
- 1.84 10^5 Pa
Answer
D) 1.84 10^5 Pa
P2 = P1 + 12rho(v1^2 - v2^2) = 2 10^5 + 500(4 - 36) = 1.84 10^5 Pa. SLO P-11-B-40 · Application
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