A spring obeying Hooke's law extends 3 cm under a final force of 6 N. The work done in stretching it is:

  1. 0.18 J
  2. 0.09 J
  3. 9 J
  4. 0.045 J
Answer

B) 0.09 J

Work = area of the triangle = 12Fe = 12(6)(0.03) = 0.09 J. SLO P-11-B-27 · Application

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