A gas at constant pressure 1 10^5 Pa changes volume from 0.002 m^3 to 0.005 m^3. The work done by the gas is:
- 30 J
- 3000 J
- 300 J
- -300 J
Answer
C) 300 J
W = pDelta V = 1 10^5 (0.005 - 0.002) = 300 J. SLO P-11-C-06 · Application
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