When 3340 J melts 10 g of ice at 273 K, the entropy of the ice increases by about:
- 3340 J/K
- 12.2 J/K
- 0.082 J/K
- 9.1 10^5 J/K
Answer
B) 12.2 J/K
Delta S = Q/T = 3340/273. SLO P-11-C-18 · Understanding
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