In a karate chop the hand exerts an average force of 500 N for 0.01 s. The impulse given is:
- 0.5 N s
- 50 N s
- 5 N s
- 10 N s
Answer
C) 5 N s
Impulse = FDelta t = 500 0.01 = 5 N s = change in momentum. SLO P-11-B-11 · Application
Physics MCQ · More Momentum and Collisions MCQs · Practise