A proton (charge 1.6 10^-19 C) moves at 40,000 m/s at 0^circ to a field of 0.8 T. The magnetic force on it is:
- 2.56 10^-15 N
- 5.12 10^-15 N
- 6.4 10^-15 N
- 0 N
Answer
D) 0 N
F = Bqvsintheta = 0 N. Moving parallel to the field, it feels no force. SLO P-09-E-32 · Application
Physics MCQ · More Magnetism and Electromagnetic Induction MCQs · Practise