Verify the distributive law of intersection over union: with A = 2, 3, 5, 6, 10, B = 2, 3, 4, 10, C = 2, 4, 6, 9, both A cap (B cup C) and (A cap B) cup (A cap C) equal:

  1. 2, 3, 4, 5, 6, 9, 10
  2. 2
  3. 2, 4, 6
  4. 2, 3, 6, 10
Answer

D) 2, 3, 6, 10

Working out each side separately gives the same set 2, 3, 6, 10, which verifies A cap (B cup C) = (A cap B) cup (A cap C). SLO M-09-A-13 · Application

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