The frequency f of a mass–spring system depends on m and spring constant ks: f = C,m^aks^b. Then
- a = 12, b = - 12
- a = - 12, b = 12
- a = 1, b = -1
- a = -1, b = 1
Answer
B) a = - 12, b = 12
T^-1 = M^a( MT^-2)^b: T: b = 12; M: a + b = 0 Rightarrow a = - 12: f = C ks/m. SLO P-11-A-04 · Application
Physics MCQ · More Physical Quantities and Measurement MCQs · Practise