The square root of (x + 1x )^2 - 4 is:

  1. pm (x - 1x )
  2. pm (x + 1x - 2 )
  3. pm(x - 2)
  4. pm (x + 1x )
Answer

A) pm (x - 1x )

(x + 1x )^2 - 4 = x^2 - 2 + 1x^2 = (x - 1x )^2. SLO M-09-A-20 · Understanding

Mathematics MCQ · More Factorization MCQs · Practise