A gas absorbs 500 J of heat and does 200 J of work. The change in its internal energy is: (Use Q = Delta U + W, where Q = heat supplied to the gas and W = work done by the gas.)

  1. 150 J
  2. 600 J
  3. 300 J
  4. 3000 J
Answer

C) 300 J

Delta U = Q - W = 500 - (200) = 300 J. SLO P-11-C-08 · Application

Physics MCQ · More Kinetic Theory and First Law of Thermodynamics MCQs · Practise