A ball is projected at 25 m/s at 53.13^circ above the horizontal (g = 9.8 m/s^2). Its time of flight is:
- 2.04 s
- 3.06 s
- 4.08 s
- 8.16 s
Answer
C) 4.08 s
T = 2usinthetag = 2(25)(0.8)9.8 = 4.08 s. SLO P-11-B-05 · Application
Physics MCQ · More Kinematics and Projectile Motion MCQs · Practise