An ice skater with I = 5 kg m^2 spins at 1 rad/s, then pulls in her arms so I = 2.5 kg m^2. Her new angular velocity is:
- 1 rad/s
- 2 rad/s
- 4 rad/s
- 0.5 rad/s
Answer
B) 2 rad/s
I1omega1 = I2omega2 Rightarrow omega2 = 5 12.5 = 2 rad/s. SLO P-11-B-20 · Application
Physics MCQ · More Circular and Rotational Motion MCQs · Practise