A gas receives 600 J of heat and its internal energy rises by 600 J. The work done by the gas is:
- 0 J
- -600 J
- 1200 J
- 600 J
Answer
A) 0 J
W = Q - Delta U = 0 (constant volume). SLO P-11-C-11 · Application
Physics MCQ · More Kinetic Theory and First Law of Thermodynamics MCQs · Practise