A wire of length 0.25 m carries 3 A at 60^circ to a uniform magnetic field of 1.2 T. The force on it is:

  1. 0.39 N
  2. 1.56 N
  3. 0.9 N
  4. 0.779 N
Answer

D) 0.779 N

F = BILsintheta = 1.2 3 0.25 sin 60^circ = 0.779 N. SLO P-09-E-30 · Application

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