A rotating space station of radius 50 m gives g = 9.8 m/s^2 at the rim. Its period of rotation is:
- 14.3 s
- 7.1 s
- 14.2 s
- 28.4 s
Answer
C) 14.2 s
omega = 0.443 rad/s, so T = 2pi/omega = 14.2 s. SLO P-11-B-17 · Understanding
Physics MCQ · More Circular and Rotational Motion MCQs · Practise