A car starts with velocity 20 m/s and accelerates at -2 m/s^2 for 6 s. The distance covered is:

  1. 84 m
  2. 48 m
  3. 168 m
  4. 42 m
Answer

A) 84 m

s = ut + 12at^2 = 20(6) + 12(-2)(6)^2 = 84 m. SLO P-11-B-04 · Application

Physics MCQ · More Kinematics and Projectile Motion MCQs · Practise