A refrigerator removes 600 J from its contents using 200 J of electrical work. The heat given out to the kitchen is:
- 400 J
- 800 J
- 200 J
- 600 J
Answer
B) 800 J
QH = QC + W = 800 J. SLO P-11-C-17 · Understanding
Physics MCQ · More Heat Engines, Second Law and Entropy MCQs · Practise