A spring's force rises linearly from 20 N at extension 0.1 m to 50 N at 0.25 m. The work done over this range is:

  1. 5.25 J
  2. 7.5 J
  3. 2.62 J
  4. 10.5 J
Answer

A) 5.25 J

Area of the trapezium = 12(20 + 50)(0.25 - 0.1) = 5.25 J. SLO P-11-B-27 · Application

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