A clock in a spaceship moving at 0.8c records 10 s (proper time). An Earth observer measures the interval as:
- 33.3 s
- 167 s
- 8.33 s
- 16.7 s
Answer
D) 16.7 s
t = γ t₀ = 10/(√(1 - 0.8²)) = 16.7 s. SLO P-11-F-05 · Understanding
Physics MCQ · More Special Relativity MCQs · Practise