A force of 10 N acts for the first 2 m, then 20 N for the next 3 m. The total work done is:

  1. 50 J
  2. 30 J
  3. 80 J
  4. 100 J
Answer

C) 80 J

10(2) + 20(3) = 20 + 60 = 80 J. SLO P-11-B-30 · Application

Physics MCQ · More Work and Energy MCQs · Practise