A string of length 1.2 m fixed at both ends vibrates in 3 loops. The wavelength is:

  1. 0.4 m
  2. 0.8 m
  3. 1.6 m
  4. 3.6 m
Answer

B) 0.8 m

Each loop is lambda2: lambda = 2Ln = 0.8 m. SLO P-11-D-10 · Application

Physics MCQ · More Superposition, Stationary Waves and Beats MCQs · Practise