A current of 3 A flows through a 4 Ω resistor. The power dissipated is:
- 72 W
- 36 W
- 18 W
- 12 W
Answer
B) 36 W
P = I^2R = (3)^2(4) = 36 W. SLO P-09-E-12 · Application
Physics MCQ · More Current Electricity MCQs · Practise
B) 36 W
P = I^2R = (3)^2(4) = 36 W. SLO P-09-E-12 · Application
Physics MCQ · More Current Electricity MCQs · Practise