A 0.15 kg cricket ball at 30 m/s is hit straight back at 20 m/s. The change in its momentum is:
- 1.5 kg m/s
- 4.5 kg m/s
- 7.5 kg m/s
- 3.0 kg m/s
Answer
C) 7.5 kg m/s
Delta p = 0.15(20 - (-30)) = 7.5 kg m/s. SLO P-11-B-11 · Application
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