A coil of area 0.25 m^2 is in a 0.2 T field; the field makes 90^circ with the normal to the coil. The flux through the coil is:
- 0 Wb
- 0.05 Wb
- 0.8 Wb
- 0.025 Wb
Answer
A) 0 Wb
Phi = BAcostheta = 0.2 0.25 cos 90^circ = 0 Wb. SLO P-09-E-39 · Application
Physics MCQ · More Magnetism and Electromagnetic Induction MCQs · Practise