A fixed mass of gas at 1 10^5 Pa occupies 6 L. At constant temperature it is changed to 2 L. The new pressure is:

  1. 3 10^5 Pa
  2. 1.5 10^5 Pa
  3. 6 10^5 Pa
  4. 33,300 Pa
Answer

A) 3 10^5 Pa

p1V1 = p2V2 Rightarrow p2 = 1 10^5 62 = 3 10^5 Pa. SLO P-11-C-10 · Application

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