Prove that the sum of three consecutive integers is divisible by 3. Writing them as n, n + 1, n + 2, the sum is:

  1. 3(n + 1)
  2. 3n + 2
  3. 3n
  4. n + 3
Answer

A) 3(n + 1)

n + (n + 1) + (n + 2) = 3n + 3 = 3(n + 1), a multiple of 3. SLO M-09-B-15 · Knowledge

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