A proton is accelerated through a p.d. of 2 10^9 V. The kinetic energy it gains is:

  1. 3.2 10^-10 J
  2. 1.6 10^-10 J
  3. 3.2 10^-9 J
  4. 6.4 10^-10 J
Answer

A) 3.2 10^-10 J

KE = eV = 1.6 10^-19 2 10^9 = 3.2 10^-10 J. SLO P-11-F-23 · Understanding

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