Plane-polarized light of intensity 80 W/m^2 is reduced to 60 W/m^2 by a polarizer. The angle between the polarization plane and the polarizer's axis is:
- 30^circ
- 15^circ
- 41.4^circ
- 60^circ
Answer
A) 30^circ
cos^2theta = 6080 Rightarrow theta = 30^circ. SLO P-11-D-06 · Understanding
Physics MCQ · More Polarization MCQs · Practise