A charge of 2 10^-6 C is placed in an electric field of 5000 N/C. The force on it is:

  1. 0.01 N
  2. 0.001 N
  3. 0.02 N
  4. 0.1 N
Answer

A) 0.01 N

F = qE = 2 10^-6 5000 = 0.01 N. SLO P-11-E-02 · Application

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