MCQs / Physics / Electrostatics

Electrostatics MCQs — Physics

120 multiple-choice questions on Electrostatics from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.

1. The Earth's field at its surface can be calculated as if all its charge (or mass) were:

  1. concentrated at its centre
  2. on the North Pole
  3. spread through space
  4. on the equator

Answer: A) concentrated at its centre

Explanation: Same principle as for a sphere. SLO P-11-E-05 · Knowledge

Discuss this question

2. An electron is accelerated from rest through a p.d. of 50 V. The kinetic energy it gains is:

  1. 8 10^-18 J
  2. 8 10^-17 J
  3. 8 10^-19 J
  4. 1.6 10^-17 J

Answer: A) 8 10^-18 J

Explanation: KE = eV = 1.6 10^-19 50 = 8 10^-18 J (= 50 eV). SLO P-11-E-04 · Understanding

Discuss this question

3. Workers on live high-voltage lines wear conductive suits that act as:

  1. Faraday cages
  2. insulators
  3. capacitors
  4. magnets

Answer: A) Faraday cages

Explanation: Protect them from the fields. SLO P-11-E-06 · Understanding

Discuss this question

4. Charges +Q and -Q are a distance d apart. The field at the midpoint is:

  1. 2kQd^2
  2. 8kQd^2
  3. 4kQd^2
  4. 0

Answer: B) 8kQd^2

Explanation: Each gives kQ(d/2)^2 = 4kQd^2 in the same direction. SLO P-11-E-08 · Application

Discuss this question

5. Inside a closed hollow conductor placed in an external electric field, the field is:

  1. zero
  2. reversed and doubled
  3. equal to outside
  4. stronger than outside

Answer: A) zero

Explanation: Electrostatic shielding. SLO P-11-E-06 · Understanding

Discuss this question

6. An electron entering a uniform electric field at right angles to the field follows:

  1. a straight line
  2. a spiral
  3. a parabolic path
  4. a circular path

Answer: C) a parabolic path

Explanation: Like a projectile: constant force perpendicular to initial velocity. SLO P-11-E-04 · Understanding

Discuss this question

7. The electric field strength due to a point charge Q at distance r is:

  1. E = kQ^2r^2
  2. E = kQr^2
  3. E = kQr^2
  4. E = kQr

Answer: C) E = kQr^2

Explanation: Inverse square law. SLO P-11-E-08 · Application

Discuss this question

8. Coaxial cables have an outer braided conductor to:

  1. carry extra current
  2. make the cable stronger
  3. cool the wire
  4. shield the inner wire from external interference

Answer: D) shield the inner wire from external interference

Explanation: Faraday shielding. SLO P-11-E-06 · Understanding

Discuss this question

9. The electric field strength 0.05 m from a point charge of 4 10^-8 C in free space is:

  1. 1.44 10^5 N/C
  2. 7190 N/C
  3. 71,900 N/C
  4. 2.88 10^5 N/C

Answer: A) 1.44 10^5 N/C

Explanation: E = kQr^2 = 8.99 10^9 4 10^-8(0.05)^2 = 1.44 10^5 N/C. SLO P-11-E-08 · Application

Discuss this question

10. A Faraday cage works because conductors contain:

  1. free electrons that can move
  2. no charges
  3. fixed ions only
  4. only protons

Answer: A) free electrons that can move

Explanation: Electrons redistribute instantly. SLO P-11-E-06 · Understanding

Discuss this question

11. For a point outside a charged spherical conductor, the charge can be treated as:

  1. located on the nearest surface point
  2. spread uniformly in space
  3. a point charge at the centre of the sphere
  4. zero

Answer: C) a point charge at the centre of the sphere

Explanation: The field outside is the same as a point charge's. SLO P-11-E-05 · Knowledge

Discuss this question

12. The field 1 m from a point charge is 9000 N/C. The charge is:

  1. 1 10^-5 C
  2. 2 10^-6 C
  3. 1 10^-6 C
  4. 5.01 10^-7 C

Answer: C) 1 10^-6 C

Explanation: Q = Er^2k = 1 10^-6 C. SLO P-11-E-08 · Application

Discuss this question

13. Coulomb's law is valid for:

  1. point charges (or spherically symmetric charges)
  2. any shape at any distance exactly
  3. only moving charges
  4. only magnets

Answer: A) point charges (or spherically symmetric charges)

Explanation: Point charges. SLO P-11-E-07 · Application

Discuss this question

14. Near a sharp point on a charged conductor, the field lines are:

  1. parallel to the surface
  2. absent
  3. far apart
  4. very close together (strong field)

Answer: D) very close together (strong field)

Explanation: Charge concentrates on sharp points. SLO P-11-E-03 · Understanding

Discuss this question

15. A charge of 1.6 10^-19 C is placed in an electric field of 10,000 N/C. The force on it is:

  1. 1.6 10^-15 N
  2. 3.2 10^-15 N
  3. 1.6 10^-16 N
  4. 1.6 10^-14 N

Answer: A) 1.6 10^-15 N

Explanation: F = qE = 1.6 10^-19 10,000 = 1.6 10^-15 N. SLO P-11-E-02 · Application

Discuss this question

16. A Faraday cage is made of:

  1. a conducting material (e.g. metal mesh)
  2. wood
  3. an insulator such as plastic
  4. glass

Answer: A) a conducting material (e.g. metal mesh)

Explanation: Free charges must move. SLO P-11-E-06 · Understanding

Discuss this question

17. The SI unit of electric field strength is:

  1. N
  2. J
  3. C
  4. N/C (or V/m)

Answer: D) N/C (or V/m)

Explanation: Force per unit charge. SLO P-11-E-01 · Knowledge

Discuss this question

18. Why is the 'point charge' model useful for spheres?

  1. it makes the field uniform
  2. it removes all charges
  3. it changes the sphere's radius
  4. it allows Coulomb's law to be used for charged spheres

Answer: D) it allows Coulomb's law to be used for charged spheres

Explanation: Simplifies calculation. SLO P-11-E-05 · Knowledge

Discuss this question

19. The charge on an isolated conducting sphere resides:

  1. at its centre
  2. on its outer surface
  3. nowhere
  4. uniformly through its volume

Answer: B) on its outer surface

Explanation: Charges repel to the surface. SLO P-11-E-05 · Knowledge

Discuss this question

20. The electric field around an isolated negative charge points:

  1. radially inward
  2. nowhere
  3. radially outward
  4. in circles

Answer: A) radially inward

Explanation: Towards negative charges. SLO P-11-E-01 · Knowledge

Discuss this question

21. Electric field strength is defined as:

  1. charge per unit force
  2. force × charge
  3. work per unit charge
  4. force per unit positive charge

Answer: D) force per unit positive charge

Explanation: E = F/q. SLO P-11-E-02 · Application

Discuss this question

22. Two parallel plates 5 cm apart have a p.d. of 1000 V between them. The field strength between them is:

  1. 20,000 V/m
  2. 2 10^5 V/m
  3. 2000 V/m
  4. 200 V/m

Answer: A) 20,000 V/m

Explanation: E = Delta VDelta d = 10000.05 = 20,000 V/m. SLO P-11-E-02 · Application

Discuss this question

23. A charge of 2 10^-6 C is placed in an electric field of 5000 N/C. The force on it is:

  1. 0.01 N
  2. 0.001 N
  3. 0.02 N
  4. 0.1 N

Answer: A) 0.01 N

Explanation: F = qE = 2 10^-6 5000 = 0.01 N. SLO P-11-E-02 · Application

Discuss this question

24. A positive charge released in a uniform electric field moves:

  1. at constant velocity
  2. in a circle
  3. against the field
  4. in the direction of the field, with uniform acceleration

Answer: D) in the direction of the field, with uniform acceleration

Explanation: Constant force qE. SLO P-11-E-04 · Understanding

Discuss this question

25. Cathode-ray oscilloscopes use deflecting plates to:

  1. heat the screen
  2. make magnetic fields
  3. move the electron beam by electric fields
  4. slow the electrons to rest

Answer: C) move the electron beam by electric fields

Explanation: Electrostatic deflection. SLO P-11-E-04 · Understanding

Discuss this question

Page 1 of 5 Next

Practise Electrostatics MCQs

More Physics chapters